Nilai dari ^(3)log(4√2 − √5) + ^(3)log(4√2 + √5) = …

Nilai dari ^(3)log(4√2 − √5) + ^(3)log(4√2 + √5) = …
A. −3
B. −2
C. 1
D. 2
E. 3

Logaritma
a² – b² = (a + b)(a – b)
log a + log b = log ab

³log (4√2 – √5) + ³log (4√2 + √5)
= ³log (4√2 – √5)(4√2 + √5)
= ³log ((4√2)² – (√5)²)
= ³log (32 – 5)
= ³log 27
= ³log 3³
= 3 . ³log 3
= 3

³log (4√2 – √5) + ³log (4√2 + √5) = 3