Diketahui A = 1 6 0 dan B =5 3 1 ,panjang vektor AB adalah….

diketahui A = 1 6 0 dan B =5 3 1 ,panjang vektor AB adalah….
A.√24
B.√26
C.√28
D.√29
E.√30

Vektor

A = (1,6,0)
B = (5,3,1)

AB = B – A
AB = (5,3,1) – (1,6,0)
AB = (4,-3,1)

Panjang vektor AB
= |AB|
= √(4² + (-3)² + 1²)
= √(16 + 9 + 1)
= √26 satuan