Hitung pH : d) 0,2 M HCN Ka = 2 × 10^-5

Hitung pH :
d) 0,2 M HCN Ka = 2 × 10^-5

[H+] = (Ka x M)^0,5
[H+] = ( (2 x 10^-5) x 0,2 )^0,5
[H+] = ( 4 x 10^-6 )^0,5
[H+] = 2 x 10^-3

pH = – log [H+]
pH = – log 2 x 10^-3
pH = – log 2 – log 10^-3
pH = 3 – log 2